This is the real example of how to determine stuck depth using the stuck depth calculation.
Well Information:
- TD = 8,900’MD/5,600’ TVD
- Bit Size = 8.5”
- Drilling fluid = water based mud (PHPA system)
- Formation: sand shale sequence
- BHA: 7” mud motor + 9 stands of 5” HWDP S-135, 4-1/2” IF connection
- Drillstring: 5” DP S135, 4-1/2” IF connection
- Neutral weight @ 6,850’MD = 175 Klb
While tripping out of hole to 6,850’MD, observe over pull 40 Klb over pick up weight. Stop tripping out and attempt to go down no issue. Attempt to rotate, pipe is able to rotate at 30K ft-lb. Attempt to circulate, observe restricted flow.
Figure 1 – Stuck While Pulling Out
Based on the information, we would expect the cutting load bed issue. We attempt to determine where the stuck point is using the stuck depth formula.
Stuck Depth (ft) = (735,294 x e x Drill Pipe Weight (ppf)) ÷ (Differential Pull, lb)
Where;
e = drill pipe stretch, inch
Pipe Stretch Information
Pull the stuck string to 300 Klb and the stretch measurement is 29.4 inch from the neutral point.
Pull the stuck string to 350 Klb and the stretch measurement is 49.2 inch from the neutral point.
So
Differential pull = 350,000 – 300,000 = 30,000 lb
e = 49.2 – 29.4 = 19.8 inch
Drill Pipe Weight (ppf) = 23.52 ppf adjusted weight
Note: The adjusted weight is used instead of the plain weight because it represents the whole string better than the plain weight. The plain pipe weight can be used for tubular as casing or tubing which don’t have tool joints.
Figure 2 – 5″DP S-135 Specification
Stuck Depth (ft) = (735,294 x 19.8 x 23.52) ÷ (50,000)
Stuck Depth (ft) = 6,784 ft
Based on this calculation, the drill string is stuck at the BHA.
Figure 3 – Stuck Location (Stuck at BHA)
Reference book: 
Formulas and Calculations for Drilling, Production and Workover, Second Edition